Chapter 4: Trigonometry
standard position: vertex=origin, initial side=(positive) x-axis
coterminal angles: same terminal side
measuring size of an angle
one full circle = 360 degrees
one full circle = 2p radians
radian measure = length of arc in circle of radius 1 swept out by the angle
acute, obtuse, reflex angles
A+B = p/2 ; complementary angles (acute)
A+B = p ; supplementary angles (acute,obtuse)
x = cost = cosine of t
y = sint = sine of t
[1/x] = [1/cost] = sect = secant of t [1/y] = [1/sint] = csct = cosecant of t
[y/y] = [sint/cost] = tant = tangent of t [x/y] = [cost/sint] = cott = cotangent of t
Examples:
sin(p/4) = cos(p/4) = Ö2/2
sin(p/6) = 1/2 ; cos(p/6) = Ö3/2
sin(p/3) = Ö3/2 ; cos(p/3) = 1/2
sin(p/2) = 1 ; cos(p/2) = 0 sin(0) = 0 ; cos(0) = 1
Domain of sint, cost : all t
Range: [-1,1]
point on circle corresp. to t+2p is same as point for t
sin(t+2p) = sint ; cos(t+2p) = cost
sint and cost are periodic
symmetry:
cost , sect are even functions
sint, csct, tant, cott are odd functions
x2+y2 = 1 (unit corcle): sin2 t+cos2 t = 1
sin(q) = a/c = (opposite)/(hypotenuse)
cos(q) = b/c = (adjacent)/(hypotenuse)
tan(q) = a/b = (opposite)/(adjacent)
``SOHCAHTOA''
Copmplementary angle = the `other' angle in a right triangle
sin(p/2-q) = cos(q) , cos(p/2-q) = sin(q)
tan(p/2-q) = cot(q) , cot(p/2-q) = tan(q)
sec(p/2-q) = csc(q) , csc(p/2-q) = sec(q)
( i.e., function(``co-angle'') = ``co-function''(angle) )
angle q, point (x,y) on terminal side
r = [Ö(x2+y2)]
sin(q) = y/r cos(q) = x/r tan(q) = y/x
reference angle = acute angle that terminal side makes with x-axis
(trig fcn)(q) = (trig fcn)(ref. angle), except possibly for a change in sign:
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III
(x < 0,y > 0) (x > 0,y > 0)
sin(q) > 0 sin(q) > 0
cos(q) < 0 cos(q) > 0
tan(q) < 0 tan(q) > 0
sin(q) < 0 sin(q) < 0
cos(q) < 0 cos(q) > 0
tan(q) > 0 tan(q) < 0
(x < 0,y < 0) (x > 0,y < 0)
IIIIV
cos(q) = x-value of the points (counter-clockwise) on the unit circle, starting with 1
Graph: note x-intercepts, y-intercept, maximum and minimum; draw a smooth curve
Transformations: y = asin(bx)
vertical stretch by factor of a; amplitude is |a|
amplitude = how far trig function wanders from its `center'
horizontal compression by factor of b; period is 2p/|b|
Translations: just like before
y = cos(x-a) ; translation to right by a
y = cos(x) +a ; translation up by a
Transformations (same)
Products: sinx, cosx bounce between -1 and 1; so, for example:
y = xsinx bounces between y = x and y = -x
y = e-xcosx bounces between y = e-x and y = -e-x (`damped' trig function)
f(x) = sinx , -p/2 £ x £ p/2 , is one-to-one
inverse is called arcsinx = angle (between -p/2 and p/2) whose sine is x
sin(arcsinx) = x ; arcsin(sinx) = x if x is between -p/2 and p/2
f(x) = cosx , 0 £ x £ p , is one-to-one
inverse is called arccosx = angle (between 0 and p) whose cosine is x
cos(arccosx) = x ; arccos(cosx) = x if x is between 0 and p
f(x) = tanx , -p/2 < x < p/2 , is one-to-one
inverse is called arctanx = angle (between -p/2 and p/2) whose tangent is x
tan(arctanx) = x ; arctan(tanx) = x if x is between -p/2 and p/2
Graphs: take appropriate piece fo trig function, and flip it across the line y = x
cos(arcsinx) = (cosine of angle whose sine is x) = [Ö(1-x2)] ; etc.
Chapter 5: Analytic trigonometry
Reciprocal: cscx = [1/sinx] secx = [1/cosx] cotx = [1/tanx]
Quotient: tanx = [sinx/cosx] cotx = [cosx/sinx]
Pythagorean: sin2 x +cos2 x = 1 tan2 x +1 = sec2 x cot2 x+1 = csc2 x
Complementarity: sin(p/2 - x) = cos(x) tan(p/2 - x) = cot(x) sec(p/2 - x) = csc(x)
cos(p/2 - x) = sin(x) cot(p/2 - x) = tan(x) csc(p/2 - x) = sec(x)
Symmetry: cos(-x) = cosx sec(-x) = secx
sin(-x) = -sinx csc(-x) = -cscx tan(-x) = -tanx cot(-x) = -cotx
Trig substitution: rewrite expression in x by `pretending' x=trig function
[Ö(a2-x2)] ; write x = asinq, then [Ö(a2-x2)] = acosq
[Ö(a2+x2)] ; write x = atanq, then [Ö(a2+x2)] = asecq
[Ö(x2-a2)] ; write x = asecq, then [Ö(x2-a2)] = ±atanq
an equation is solved for the correct values of x
Basic idea: use identities that we already know (like the list above)
convert things to sines and cosines
play with the two sides of the identity
add 0 ! multply and divide by the same expression!
Examples: cscx-sinx = [1/secxtanx]
[(tanx+tany)/(1-tanx tany)] = [(cotx+coty)/(cotxcoty-1)]
(single trig function) = (single value)
Wrinkles:
Polynomials: 2cos2x+3cosx+1 = 0 ; (2cosx+1)(cosx+1) = 0
2cosx+1 = 0 or cosx+1 = 0
Trig identities: tanx+secx=4 ; tanx = 4-secx ; square both sides
tan2 x (= sec2 x-1) = 16-8secx+sec2 x = ....
Problem: `ghost solutions' = solutions which `appear' only after manipulating equation
(stupid) Ex: sinx = 1 and (sinx)2 = 1 have different sets of solutions!
sin(A-B) = sinAcosB-cosAsinB
cos(A+B) = cosAcosB-sinAsinB
cos(A-B) = cosAcosB+sinAsinB
Note: it is easy to derive any threee formulas from the remaining one, using even/odd and complementarity formulas.
tan(A+B)= [(sin(A+B))/(cos(A+B))] = [(tanA+tanB)/(1-tanAtanB)]
tan(A-B)= [(sin(A-B))/(cos(A-B))] = [(tanA-tanB)/(1+tanAtanB)]
Some uses: complex multiplication! (side trip to part of Section 6.5)
(a+bi)(c+di) = (ac-bd)+(ad+bc)i
pretend z=a+bi=cosA+isinA, z¢=c+di=cosB+isinB, then this reads
z·z¢=(cosAcosB-sinAsinB)+(sinAcosB+cosAsinB)i
=cos(A+B) = isin(A+B)
Problem: z=a+bi=cosA+isinA. then a2+b2=sin2 A+cos2 A=1 (every time)
Solution: think z=a+bi=r(cosA+isinA), where
r2=a2+b2;. i.e, think z« (a,b) (in plane) = point in plane at distance r
from origin, making angle A with (positive) x-axis
i.e., think z=a+bi « (a,b) « (distance,angle) ; polar coordinates
then complex multiplication multiplies distance and adds angles:
(r(cosA+isinA))(r¢(cosB+isinB)) = (rr¢)(cos(A+B)+isin(A+B))
Another use: find values of trig functions at new angles:
Example: 105° = 60° +45° (i.e. 7p/12 = p/3+p/4), so
cos(7p/12) = cos(p/3+p/4) = cos(p/3)cos(p/4)-sin(p/3)sin(p/4) =
(1/2)(Ö2/2)-(Ö3/2)(Ö2/2) = (Ö2-Ö6)/4
sin(2A) = sin(A+A) = 2sinAcosA
cos(2A) = cos(A+A) = cos2 A-sin2 a = 2cos2 a-1 = 1-2sin2 A
Triple angle? sin(3A)=sin(2A+A)=....
sin2 x=(1-cos(2x))/2 , cos2 x=(1+cos(2x))/2 ; these give
Half-angle formulas:
sin(x/2) = Ö{(1-cosx)/2} ; cos(x/2) = Ö{(1+cosx)/2}
tan(x/2) = [sinx/(1+cosx)] = [(1-cosx)/sinx]
Product-to-sum formulas:
sin(A+B)+sin(A-B) = 2sinAcosB, so
sinAcosB= [1/2](sin(A+B)+sin(A-B)) Simlarly,
cosAcosB = [1/2](cos(A+B)+cos(A-B)), and
sinAsinB = [1/2](cos(A-B)-cos(A+B))
Sum-to-product formulas:
set A+B = x, A-B = y (solve: A=[(x+y)/2], B=[(x-y)/2]), plug in above!
sinx+siny = 2sin[(x+y)/2]cos[(x-y)/2]
cosx+cosy = 2cos[(x+y)/2]cos[(x-y)/2]
cosx-cosy = 2sin[(x+y)/2]sin[(x-y)/2]
OK, so what's the point? It's alot easier to remember what these formulas (in the
previous two sections) say if
you remember where they come from. We built all of these formulas up from one
formula; cos(A-B) = ..... . If you remember how each follows one from the other, then you
don't `have to' remember the formula!